線形代数例

$[\begin{array}{c} a & b & c \\ d & e & f \\ g & h & i \end{array}] \cdot [\begin{array}{c} - 3 & - 3 & - 2 \\ 1 & - 5 & 5 \\ - 3 & - 1 & 3 \end{array}] = [\begin{array}{c} - 3 & - 1 & 3 \\ 1 & - 5 & 5 \\ - 3 & - 3 & - 2 \end{array}]$

ステップ 1

The table does not have enough points.

The table does not have a function rule.

線形代数 例

線形代数例